Probabilistic consideration on chances of invasion between states -- a symmetry
The probability P(k) of being invaded simultaneously by particular k states is
(please use monospaced font because
3 lines are used for each expression.)
p k p n-k
P(k) = ( - ) (1- - )
n n
and its number of cases is C .
n k
Then the total expectation of frequency of invasion by all of other states is
n n p k p n-k
<f> = · k C P(k) = · k C ( - ) (1- - )
k=1 n k k=1 n k n n
n n-k r p k p r
= · · k C C (-1) ( - ) ( - )
k=1 r=0 n k n-k r n n
n n-k n! r p k+r
= · · ----------------- (-1) ( - )
k=1 r=0 (k-1)!(n-k-r)!r! n
Changing the summation indices k and r into s=k+r and r, this expression becomes
n s-1 n! r p s
<f> = · · ----------------- (-1) ( - )
s=1 r=0 (s-r-1)!(n-s)!r! n
n n! p s s-1 1 r
= · ------ ( - ) · ----------- (-1)
s=1 (n-s)! n r=0 (s-r-1)!r!
n! p 1
= ------ ( - )
(n-1)! n
n n! p s s-1 1 r
+ · ------ ( - ) · ----------- (-1)
s=2 (n-s)! n r=0 (s-r-1)!r!
The last summation of the 2nd term is zero because
it is simply an expansion of
s-1
(1 - 1)
divided by (s-1)!.
So that, is simply equal to p.
This result is anticipated because "defensive war" and "aggression" are only different names for a same event, the war.